This video shows how to use vertex form ie y = a(x h)² k to graph a parabola or use it to write an equation from a graph This lesson was created foLatus Rectum of a Parabola Opening to the Right The given quadratic equation follows the form {eq}(yk)^2=4p(xh){/eq} Since the coefficient of {eq}x{/eq} is positive, its graph is a parabolaThe equation of a parabola with a horizontal axis is written as x = \dfrac {1} {4p} (y k)^2 h with vertex V (h,k) and focus F (hp,k) and directrix given by the equation x = h p Example 3 Find the vertex, focus and directrix of the parabola given by the equation x = \dfrac {1} {4} y^2 y 11
Conic Sections Calculus Volume 2
